What is expand (ln((y^2-1)(x^2-1)))/2 ?

The solution to expand (ln((y^2-1)(x^2-1)))/2 is (ln(y^2x^2-y^2-x^2+1))/2

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expand (ln((y^2-1)(x^2-1)))/2

expand

\frac{ln ( ( y ^{2} - 1 ) ( x ^{2} - 1 ) )}{2}

\frac{ln ( y ^{2} x ^{2} - y ^{2} - x ^{2} + 1 )}{2}

Solution steps

\frac{ln ( ( y ^{2} - 1 ) ( x ^{2} - 1 ) )}{2}

Expand

(y^{2} - 1) (x^{2} - 1) : y^{2} x^{2} - y^{2} - x^{2} + 1

= \frac{ln ( y ^{2} x ^{2} - y ^{2} - x ^{2} + 1 )}{2}

(cos (θ) + i sin (θ))^{6}

\frac{d}{d v} ((p) (p + \frac{9.5}{v ^{2}}) (v - 9.8))

3 (a - \frac{1}{6})^{2} - \frac{49}{12}

(1 - x + x^{2})^{5}

(y - 5)^{2}

What is expand (ln((y^2-1)(x^2-1)))/2 ?
The solution to expand (ln((y^2-1)(x^2-1)))/2 is (ln(y^2x^2-y^2-x^2+1))/2