What is (t-1/4)(t-3/4) ?

The solution to (t-1/4)(t-3/4) is ((4t-1)(4t-3))/(16)

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simplify (t-1/4)(t-3/4)

simplify

(t - \frac{1}{4}) (t - \frac{3}{4})

\frac{( 4 t - 1 ) ( 4 t - 3 )}{16}

Solution steps

(t - \frac{1}{4}) (t - \frac{3}{4})

Simplify

t - \frac{1}{4} : \frac{4 t - 1}{4}

= \frac{4 t - 1}{4} (t - \frac{3}{4})

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 4 t - 1 ) ( t - \frac{3}{4} )}{4}

Simplify

(4 t - 1) (t - \frac{3}{4}) : \frac{( 4 t - 1 ) ( t \cdot 4 - 3 )}{4}

= \frac{\frac{( 4 t - 1 ) ( t \cdot 4 - 3 )}{4}}{4}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 4 t - 1 ) ( t \cdot 4 - 3 )}{4 \cdot 4}

Multiply the numbers:

4 \cdot 4 = 16

= \frac{( 4 t - 1 ) ( t \cdot 4 - 3 )}{16}

= \frac{( 4 t - 1 ) ( 4 t - 3 )}{16}

2 (x - 2) (x - 2) (x + 2)

(\frac{4}{16} x + \frac{5}{16} y + \frac{3}{16} z + \frac{4}{16} t)^{4}

(4 + 2 i)^{5}

e^{(1 + 2 i) t}

\frac{π h ^{2} ( 3 r - h )}{3}