What is expand (2x^{2/3}y+xy^{3/4})^2 ?

The solution to expand (2x^{2/3}y+xy^{3/4})^2 is 4x^{4/3}y^2+4x^{5/3}y^{7/4}+x^2y^{3/2}

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expand (2x^{2/3}y+xy^{3/4})^2

expand

(2 x^{\frac{2}{3}} y + x y^{\frac{3}{4}})^{2}

4 x^{\frac{4}{3}} y^{2} + 4 x^{\frac{5}{3}} y^{\frac{7}{4}} + x^{2} y^{\frac{3}{2}}

Solution steps

(2 x^{\frac{2}{3}} y + x y^{\frac{3}{4}})^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(2 x^{\frac{2}{3}} y + x y^{\frac{3}{4}})^{2} = (2 x^{\frac{2}{3}} y)^{2} + 2 \cdot 2 x^{\frac{2}{3}} y x y^{\frac{3}{4}} + (x y^{\frac{3}{4}})^{2}

= (2 x^{\frac{2}{3}} y)^{2} + 2 \cdot 2 x^{\frac{2}{3}} y x y^{\frac{3}{4}} + (x y^{\frac{3}{4}})^{2}

(2 x^{\frac{2}{3}} y)^{2} = 4 x^{\frac{4}{3}} y^{2}

2 \cdot 2 x^{\frac{2}{3}} y x y^{\frac{3}{4}} = 4 x^{\frac{5}{3}} y^{\frac{7}{4}}

(x y^{\frac{3}{4}})^{2} = x^{2} y^{\frac{3}{2}}

= 4 x^{\frac{4}{3}} y^{2} + 4 x^{\frac{5}{3}} y^{\frac{7}{4}} + x^{2} y^{\frac{3}{2}}

2.66 (u - 6 - 7.17 = 9.83)

24 (2 + 3) 2 - 3

\frac{( x ^{2} + 3 )}{( x + 1 ) ^{2}}

\frac{10 s}{( s + 1 ) ( s + 2 ) ( s + 3 )}

3 x^{2} + 6 x y + (3 x^{2} + 2 y) y^{'} (x)

What is expand (2x^{2/3}y+xy^{3/4})^2 ?
The solution to expand (2x^{2/3}y+xy^{3/4})^2 is 4x^{4/3}y^2+4x^{5/3}y^{7/4}+x^2y^{3/2}