What is expand (\times+3)(x^2-3x+9) ?

The solution to expand (\times+3)(x^2-3x+9) is 3x^2-9x+27

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expand (\times+3)(x^2-3x+9)

expand

(\cdot + 3) (x^{2} - 3 x + 9)

3 x^{2} - 9 x + 27

Solution steps

(3) (x^{2} - 3 x + 9)

Distribute parentheses

= (3) x^{2} + (3) (- 3 x) + (3) \cdot 9

Apply minus-plus rules

+ (- a) = - a

= (3) x^{2} - (3) \cdot 3 x + (3) \cdot 9

Simplify

(3) x^{2} - (3) \cdot 3 x + (3) \cdot 9 : 3 x^{2} - 9 x + 27

= 3 x^{2} - 9 x + 27

(y - x y^{2} + 2 y e^{x}) d x + (x - x^{2} y + 2 e^{x}) d y

(1 - i w)^{2}

a ln (\frac{am}{( a + b ) t}) + b ln (\frac{bm}{( a + b ) t})

\frac{( 8 ( a ^{2} - s ^{2} ) )}{( a ^{2} + s ^{2} ) ^{2}}

\frac{1}{s ^{4} ( s ^{2} + 1 )}

What is expand (\times+3)(x^2-3x+9) ?
The solution to expand (\times+3)(x^2-3x+9) is 3x^2-9x+27