What is expand f(x)(2x+1)+g(x)(-4x-1)' ?

The solution to expand f(x)(2x+1)+g(x)(-4x-1)' is 2xf(x)+f(x)+g(x)(-4x-1)'

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expand f(x)(2x+1)+g(x)(-4x-1)'

expand

f (x) (2 x + 1) + g (x) (- 4 x - 1)^{'}

2 x f (x) + f (x) + g (x) (- 4 x - 1)'

Solution steps

f (x) (2 x + 1) + g (x) (- 4 x - 1)^{'}

Expand

f (x) (2 x + 1) : 2 x f (x) + f (x)

= 2 x f (x) + f (x) + g (x) (- 4 x - 1)^{'}

9 (2 x + 4 x)^{2}

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\frac{sin ( 2 x ) ( cot ( x ) - csc ( x ) )}{cot ( x ) + csc ( x )}

\frac{2 x ^{5} - x ^{4} + 3 x ^{3} - a x ^{2} + b x - c}{( x - 1 ) ^{3}}

What is expand f(x)(2x+1)+g(x)(-4x-1)' ?
The solution to expand f(x)(2x+1)+g(x)(-4x-1)' is 2xf(x)+f(x)+g(x)(-4x-1)'