What is expand (e^{-5s}(2s+3))/(s(s^2+2s+5)) ?

The solution to expand (e^{-5s}(2s+3))/(s(s^2+2s+5)) is (2e^{-5s}s+3e^{-5s})/(s^3+2s^2+5s)

Popular >

expand (e^{-5s}(2s+3))/(s(s^2+2s+5))

expand

\frac{e ^{- 5 s} ( 2 s + 3 )}{s ( s ^{2} + 2 s + 5 )}

\frac{2 e ^{- 5 s} s + 3 e ^{- 5 s}}{s ^{3} + 2 s ^{2} + 5 s}

Solution steps

\frac{e ^{- 5 s} ( 2 s + 3 )}{s ( s ^{2} + 2 s + 5 )}

Expand

s (s^{2} + 2 s + 5) : s^{3} + 2 s^{2} + 5 s

= \frac{e ^{- 5 s} ( 2 s + 3 )}{s ^{3} + 2 s ^{2} + 5 s}

Expand

e^{- 5 s} (2 s + 3) : 2 e^{- 5 s} s + 3 e^{- 5 s}

= \frac{2 e ^{- 5 s} s + 3 e ^{- 5 s}}{s ^{3} + 2 s ^{2} + 5 s}

\frac{d}{d y} ((x (y)) (\frac{y ^{4}}{4} + \frac{1}{8 y ^{2}}))

m^{\frac{1}{3}} (m^{2} - 3 m)

\frac{d ^{2}}{d ^{2} x} (y^{4} + 3 y - 4 x^{3} = 5 x + 1)

(y^{2} - x^{2}) \frac{d y}{d x}

\frac{( - 9 x + 8 ) ( x - 8 )}{( - 9 x - 8 ) x}

What is expand (e^{-5s}(2s+3))/(s(s^2+2s+5)) ?
The solution to expand (e^{-5s}(2s+3))/(s(s^2+2s+5)) is (2e^{-5s}s+3e^{-5s})/(s^3+2s^2+5s)