What is expand ((4x-1)^2)/(16) ?

The solution to expand ((4x-1)^2)/(16) is x^2-x/2+1/16

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expand ((4x-1)^2)/(16)

expand

\frac{( 4 x - 1 ) ^{2}}{16}

x^{2} - \frac{x}{2} + \frac{1}{16}

Solution steps

\frac{( 4 x - 1 ) ^{2}}{16}

(4 x - 1)^{2} = 16 x^{2} - 8 x + 1

= \frac{16 x ^{2} - 8 x + 1}{16}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{16 x ^{2} - 8 x + 1}{16} = \frac{16 x ^{2}}{16} - \frac{8 x}{16} + \frac{1}{16}

= \frac{16 x ^{2}}{16} - \frac{8 x}{16} + \frac{1}{16}

Divide the numbers:

\frac{16}{16} = 1

= x^{2} - \frac{8 x}{16} + \frac{1}{16}

Cancel

\frac{8 x}{16} : \frac{x}{2}

= x^{2} - \frac{x}{2} + \frac{1}{16}

C (- 3, - 5)

(2 + x 5)^{2}

(3 x + 7)^{2}

(2 + x - 2)^{2}

(\frac{x}{3} - \frac{y}{2})^{5}

What is expand ((4x-1)^2)/(16) ?
The solution to expand ((4x-1)^2)/(16) is x^2-x/2+1/16