What is (sqrt(2x+1)-3)^2 ?

The solution to (sqrt(2x+1)-3)^2 is 2x-6sqrt(2x+1)+10

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simplify (sqrt(2x+1)-3)^2

simplify

(2 x + 1 - 3)^{2}

2 x - 6 2 x + 1 + 10

Solution steps

(2 x + 1 - 3)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(2 x + 1 - 3)^{2} = (2 x + 1)^{2} - 2 2 x + 1 \cdot 3 + 3^{2}

= (2 x + 1)^{2} - 2 2 x + 1 \cdot 3 + 3^{2}

Simplify

(2 x + 1)^{2} - 2 2 x + 1 \cdot 3 + 3^{2} : 2 x - 6 2 x + 1 + 10

= 2 x - 6 2 x + 1 + 10

\frac{x ^{2} + 1}{( x + 1 ) ( x ^{2} + 4 )}

\frac{1}{2} (u^{2} - 4 + u)

- \frac{L ( 27 B + 8 α + γ )}{54}

2^{x} l e f t (2^{n} - 1)

\frac{( 3 - x ) ( 2 - x )}{2}

What is (sqrt(2x+1)-3)^2 ?
The solution to (sqrt(2x+1)-3)^2 is 2x-6sqrt(2x+1)+10