What is expand 2(3x+1=12-4x) ?

The solution to expand 2(3x+1=12-4x) is 6x+2=12-8x

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expand 2(3x+1=12-4x)

expand

2 (3 x + 1 = 12 - 4 x)

6 x + 2 = 12 - 8 x

Solution steps

2 (3 x + 1 = 12 - 4 x)

= 2 (3 x + 1 \cdot 12 = - 4 x)

Distribute parentheses

2 \cdot 3 x + 2 \cdot 1 = 12 + 2 (- 4 x)

Apply minus-plus rules

+ (- a) = - a

2 \cdot 3 x + 2 \cdot 1 = 12 - 2 \cdot 4 x

Simplify

2 \cdot 3 x + 2 \cdot 1 = 12 - 2 \cdot 4 x : 6 x + 2 = 12 - 8 x

6 x + 2 = 12 - 8 x

(2 x y^{2} - 3) d x + (2 x^{2} y + 4) d y

x^{\frac{4}{5}} (10 x - 40)^{2}

(2 a - 3 b)^{2}

\frac{1}{3} (x - 5)^{3}

(3 + 7) (2 + 10)

What is expand 2(3x+1=12-4x) ?
The solution to expand 2(3x+1=12-4x) is 6x+2=12-8x