What is expand (-2sin(x)-2sin(2x))^2 ?

The solution to expand (-2sin(x)-2sin(2x))^2 is 4sin^2(x)+8sin(x)sin(2x)+4sin^2(2x)

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expand (-2sin(x)-2sin(2x))^2

expand

(- 2 sin (x) - 2 sin (2 x))^{2}

4 sin^{2} (x) + 8 sin (x) sin (2 x) + 4 sin^{2} (2 x)

Solution steps

(- 2 sin (x) - 2 sin (2 x))^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(- 2 sin (x) - 2 sin (2 x))^{2} = (- 2 sin (x))^{2} - 2 (- 2 sin (x)) \cdot 2 sin (2 x) + (2 sin (2 x))^{2}

= (- 2 sin (x))^{2} - 2 (- 2 sin (x)) \cdot 2 sin (2 x) + (2 sin (2 x))^{2}

Simplify

(- 2 sin (x))^{2} - 2 (- 2 sin (x)) \cdot 2 sin (2 x) + (2 sin (2 x))^{2} : 4 sin^{2} (x) + 8 sin (x) sin (2 x) + 4 sin^{2} (2 x)

= 4 sin^{2} (x) + 8 sin (x) sin (2 x) + 4 sin^{2} (2 x)

- \frac{1}{x ( 1 - ln ( x ) )}

\frac{192 x ^{2} - 48 x + 5}{( 8 x - 5 ) ^{6}}

\frac{- 3 s - 5 - 9 e ^{- 6 s}}{( 2 s + 8 ) ( s + 10 )}

\frac{d}{d y} ((z) (z^{2} - 2 z y + 3 y^{2}))

(\frac{x + 1}{2})^{2}

What is expand (-2sin(x)-2sin(2x))^2 ?
The solution to expand (-2sin(x)-2sin(2x))^2 is 4sin^2(x)+8sin(x)sin(2x)+4sin^2(2x)