What is expand (rsin(θ)-3)^2 ?

The solution to expand (rsin(θ)-3)^2 is r^2sin^2(θ)-6rsin(θ)+9

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expand (rsin(θ)-3)^2

expand

(r sin (θ) - 3)^{2}

r^{2} sin^{2} (θ) - 6 r sin (θ) + 9

Solution steps

(r sin (θ) - 3)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(r sin (θ) - 3)^{2} = (r sin (θ))^{2} - 2 r sin (θ) \cdot 3 + 3^{2}

= (r sin (θ))^{2} - 2 r sin (θ) \cdot 3 + 3^{2}

Simplify

(r sin (θ))^{2} - 2 r sin (θ) \cdot 3 + 3^{2} : r^{2} sin^{2} (θ) - 6 r sin (θ) + 9

= r^{2} sin^{2} (θ) - 6 r sin (θ) + 9

5 (2^{x} + x)^{4} (2^{x} ln (2) + 1)

(- 1 + 3)^{4}

(3 x^{2} + 6 x y^{2}) d x + (6 x^{2} y + 4 y^{3}) d y

\frac{1}{( t ^{2} - 1 ) ^{2}}

(- 3, 2, - 2) y (- 2, 3, - 4)

What is expand (rsin(θ)-3)^2 ?
The solution to expand (rsin(θ)-3)^2 is r^2sin^2(θ)-6rsin(θ)+9