What is expand e^x(2x^2+x-8) ?

The solution to expand e^x(2x^2+x-8) is 2e^xx^2+e^xx-8e^x

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expand e^x(2x^2+x-8)

expand

e^{x} (2 x^{2} + x - 8)

2 e^{x} x^{2} + e^{x} x - 8 e^{x}

Solution steps

e^{x} (2 x^{2} + x - 8)

Distribute parentheses

= e^{x} \cdot 2 x^{2} + e^{x} x + e^{x} (- 8)

Apply minus-plus rules

+ (- a) = - a

= 2 e^{x} x^{2} + e^{x} x - 8 e^{x}

\frac{1}{8} (x - \frac{1}{4} sin (4 x))

(2 x + 2)!

\frac{s - 1}{( s - 2 ) ( s ^{2} - 2 )}

(1 + 2 i)^{4} + (1 - 2 i)^{4}

\frac{7 x ^{2} - 6 x + 9}{3 x ( 4 x ^{2} + 9 )}

What is expand e^x(2x^2+x-8) ?
The solution to expand e^x(2x^2+x-8) is 2e^xx^2+e^xx-8e^x