What is ((d^2}{4r^2}-\frac{dcos(θ))/r)^3 ?

The solution to ((d^2}{4r^2}-\frac{dcos(θ))/r)^3 is ((d^2-4dcos(θ)r)^3)/(64r^6)

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simplify ((d^2}{4r^2}-\frac{dcos(θ))/r)^3

simplify

(\frac{d ^{2}}{4 r ^{2}} - \frac{d cos ( θ )}{r})^{3}

\frac{( d ^{2} - 4 d cos ( θ ) r ) ^{3}}{64 r ^{6}}

Solution steps

(\frac{d ^{2}}{4 r ^{2}} - \frac{d cos ( θ )}{r})^{3}

Simplify

\frac{d ^{2}}{4 r ^{2}} - \frac{d cos ( θ )}{r} : \frac{d ^{2} - 4 d cos ( θ ) r}{4 r ^{2}}

= (\frac{d ^{2} - 4 d cos ( θ ) r}{4 r ^{2}})^{3}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( d ^{2} - 4 d cos ( θ ) r ) ^{3}}{( 4 r ^{2} ) ^{3}}

Simplify

(4 r^{2})^{3} : 64 r^{6}

= \frac{( d ^{2} - 4 d cos ( θ ) r ) ^{3}}{64 r ^{6}}

(5 - 2 a)^{2}

\frac{2 ( 5 t ^{3} + C )}{7}

10 (3 - 1)

2 (4 + 32)

x (1 - x)

What is ((d^2}{4r^2}-\frac{dcos(θ))/r)^3 ?
The solution to ((d^2}{4r^2}-\frac{dcos(θ))/r)^3 is ((d^2-4dcos(θ)r)^3)/(64r^6)