What is expand (5x-8)/((x+1)(x-1)) ?

The solution to expand (5x-8)/((x+1)(x-1)) is (5x-8)/(x^2-1)

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expand (5x-8)/((x+1)(x-1))

expand

\frac{5 x - 8}{( x + 1 ) ( x - 1 )}

\frac{5 x - 8}{x ^{2} - 1}

Solution steps

\frac{5 x - 8}{( x + 1 ) ( x - 1 )}

Expand

(x + 1) (x - 1) : x^{2} - 1

= \frac{5 x - 8}{x ^{2} - 1}

(x - \frac{y}{y ^{'} ( x )})^{2} + (y - x y^{'} (x))^{2}

\frac{1}{s ( t s + 1 )}

\frac{x}{( x + B ) ( x - A )}

(x - 3) (x - \frac{5}{2})

(5 + cos (x)) cos (y) cos (x)

What is expand (5x-8)/((x+1)(x-1)) ?
The solution to expand (5x-8)/((x+1)(x-1)) is (5x-8)/(x^2-1)