What is (sqrt(((x^2-4))/x)-k)^2 ?

The solution to (sqrt(((x^2-4))/x)-k)^2 is (x^2-4-2ksqrt((x^2-4)/x)x+k^2x)/(x)

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simplify (sqrt(((x^2-4))/x)-k)^2

simplify

(\frac{( x ^{2} - 4 )}{x} - k)^{2}

\frac{x ^{2} - 4 - 2 k \frac{x ^{2} - 4}{x} x + k ^{2} x}{x}

Solution steps

(\frac{x ^{2} - 4}{x} - k)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(\frac{x ^{2} - 4}{x} - k)^{2} = (\frac{x ^{2} - 4}{x})^{2} - 2 \frac{x ^{2} - 4}{x} k + k^{2}

= (\frac{x ^{2} - 4}{x})^{2} - 2 \frac{x ^{2} - 4}{x} k + k^{2}

Simplify

(\frac{x ^{2} - 4}{x})^{2} - 2 \frac{x ^{2} - 4}{x} k + k^{2} : \frac{x ^{2} - 4 - 2 k \frac{x ^{2} - 4}{x} x + k ^{2} x}{x}

= \frac{x ^{2} - 4 - 2 k \frac{x ^{2} - 4}{x} x + k ^{2} x}{x}

\frac{4 - s}{( s + 2 j ) ( s - 2 j ) ( s + 1 )}

\frac{\frac{d}{d x} ( 2 x ^{2} ) - 13 x + 22}{( x - 2 ) ^{2}}

d (1 + x e^{y})

(sin (2 t) + cos (2 t))^{2}

(x + \frac{2}{7}) (x - \frac{1}{7})

What is (sqrt(((x^2-4))/x)-k)^2 ?
The solution to (sqrt(((x^2-4))/x)-k)^2 is (x^2-4-2ksqrt((x^2-4)/x)x+k^2x)/(x)