What is expand (3cos(θ)+2sin(θ))^2 ?

The solution to expand (3cos(θ)+2sin(θ))^2 is 9cos^2(θ)+12cos(θ)sin(θ)+4sin^2(θ)

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expand (3cos(θ)+2sin(θ))^2

expand

(3 cos (θ) + 2 sin (θ))^{2}

9 cos^{2} (θ) + 12 cos (θ) sin (θ) + 4 sin^{2} (θ)

Solution steps

(3 cos (θ) + 2 sin (θ))^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(3 cos (θ) + 2 sin (θ))^{2} = (3 cos (θ))^{2} + 2 \cdot 3 cos (θ) \cdot 2 sin (θ) + (2 sin (θ))^{2}

= (3 cos (θ))^{2} + 2 \cdot 3 cos (θ) \cdot 2 sin (θ) + (2 sin (θ))^{2}

Simplify

(3 cos (θ))^{2} + 2 \cdot 3 cos (θ) \cdot 2 sin (θ) + (2 sin (θ))^{2} : 9 cos^{2} (θ) + 12 cos (θ) sin (θ) + 4 sin^{2} (θ)

= 9 cos^{2} (θ) + 12 cos (θ) sin (θ) + 4 sin^{2} (θ)

(2 x + 1)^{2} d x

\frac{e ^{- 2 - 2} ( 3 + 2 2 )}{8}

\frac{4}{3} (15 - 6 y - 7 = - 11)

(a + b + c)^{5}

\frac{x ^{2} - 4 x + 1}{( x - 2 ) ^{2}}

What is expand (3cos(θ)+2sin(θ))^2 ?
The solution to expand (3cos(θ)+2sin(θ))^2 is 9cos^2(θ)+12cos(θ)sin(θ)+4sin^2(θ)