What is expand 8/((x-1)(x+1)(x+3)) ?

The solution to expand 8/((x-1)(x+1)(x+3)) is 8/(x^3+3x^2-x-3)

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expand 8/((x-1)(x+1)(x+3))

expand

\frac{8}{( x - 1 ) ( x + 1 ) ( x + 3 )}

\frac{8}{x ^{3} + 3 x ^{2} - x - 3}

Solution steps

\frac{8}{( x - 1 ) ( x + 1 ) ( x + 3 )}

Expand

(x - 1) (x + 1) (x + 3) : x^{3} + 3 x^{2} - x - 3

= \frac{8}{x ^{3} + 3 x ^{2} - x - 3}

\frac{18 s ^{2}}{( s + 1 ) ( s + 4 )}

A (- 2, - 3) y B (2, 2)

6 (1 + \frac{1}{3 s})

a + b - 2 c - 3 a + 3 b + 2 (a + b + c)

(3 - 4 x)^{2}

What is expand 8/((x-1)(x+1)(x+3)) ?
The solution to expand 8/((x-1)(x+1)(x+3)) is 8/(x^3+3x^2-x-3)