What is (3+(3i)/n)^2 ?

The solution to (3+(3i)/n)^2 is (9n^2-9}{n^2}+\frac{18)/n i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (3+(3i)/n)^2

simplify

(3 + \frac{3 i}{n})^{2}

\frac{9 n ^{2} - 9}{n ^{2}} + \frac{18}{n} i

Solution steps

(3 + \frac{3 i}{n})^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(3 + \frac{3 i}{n})^{2} = 3^{2} + 2 \cdot 3 \cdot \frac{3 i}{n} + (\frac{3 i}{n})^{2}

= 3^{2} + 2 \cdot 3 \cdot \frac{3 i}{n} + (\frac{3 i}{n})^{2}

Simplify

3^{2} + 2 \cdot 3 \cdot \frac{3 i}{n} + (\frac{3 i}{n})^{2} : \frac{9 n ^{2} - 9}{n ^{2}} + \frac{18}{n} i

= \frac{9 n ^{2} - 9}{n ^{2}} + \frac{18}{n} i

(4 + 3) (1 + 3)

\frac{( 4 - r ^{2} ) ^{2}}{2}

\frac{d ^{2}}{d x ^{2}} ((y) y^{2} (6 - 2 x))

\frac{s + e ^{- π s} - e ^{- 2 π s}}{s ( s ^{2} + 1 )}

(3 p - 5) (p + 55)

What is (3+(3i)/n)^2 ?
The solution to (3+(3i)/n)^2 is (9n^2-9}{n^2}+\frac{18)/n i