What is expand (2x^2-4x-3)/((x+1)(2x-1)) ?

The solution to expand (2x^2-4x-3)/((x+1)(2x-1)) is (2x^2-4x-3)/(2x^2+x-1)

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expand (2x^2-4x-3)/((x+1)(2x-1))

expand

\frac{2 x ^{2} - 4 x - 3}{( x + 1 ) ( 2 x - 1 )}

\frac{2 x ^{2} - 4 x - 3}{2 x ^{2} + x - 1}

Solution steps

\frac{2 x ^{2} - 4 x - 3}{( x + 1 ) ( 2 x - 1 )}

Expand

(x + 1) (2 x - 1) : 2 x^{2} + x - 1

= \frac{2 x ^{2} - 4 x - 3}{2 x ^{2} + x - 1}

\frac{2 s}{( s - 1 ) ( s ^{2} + 25 )}

\frac{d}{d y} ((x) (1 + 3 x)^{5})

y^{2} d x + (3 x y + y^{2} - 1) d y

\frac{8 ( x ^{2} + 4 )}{( 49 - x ^{2} ) ^{7}}

(1 - x 7)^{2}

What is expand (2x^2-4x-3)/((x+1)(2x-1)) ?
The solution to expand (2x^2-4x-3)/((x+1)(2x-1)) is (2x^2-4x-3)/(2x^2+x-1)