What is expand (-1/20 (x-50))^2 ?

The solution to expand (-1/20 (x-50))^2 is (x^2)/(400)-x/4+25/4

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expand (-1/20 (x-50))^2

expand

(- \frac{1}{20} (x - 50))^{2}

\frac{x ^{2}}{400} - \frac{x}{4} + \frac{25}{4}

Solution steps

(- \frac{1}{20} (x - 50))^{2}

Apply exponent rule:

(- a)^{n} = a^{n},

n

is even

(- \frac{1}{20} (x - 50))^{2} = (\frac{1}{20} (x - 50))^{2}

= (\frac{1}{20} (x - 50))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

= (\frac{1}{20})^{2} (x - 50)^{2}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

(\frac{1}{20})^{2} = \frac{1 ^{2}}{2 0 ^{2}}

= \frac{1 ^{2}}{2 0 ^{2}} (x - 50)^{2}

Apply rule

1^{a} = 1

1^{2} = 1

= \frac{1}{2 0 ^{2}} (x - 50)^{2}

(x - 50)^{2} = x^{2} - 100 x + 2500

= \frac{1}{2 0 ^{2}} (x^{2} - 100 x + 2500)

2 0^{2} = 400

= \frac{1}{400} (x^{2} - 100 x + 2500)

Distribute parentheses

= \frac{1}{400} x^{2} + \frac{1}{400} (- 100 x) + \frac{1}{400} \cdot 2500

Apply minus-plus rules

+ (- a) = - a

= \frac{1}{400} x^{2} - 100 \cdot \frac{1}{400} x + 2500 \cdot \frac{1}{400}

Simplify

\frac{1}{400} x^{2} - 100 \cdot \frac{1}{400} x + 2500 \cdot \frac{1}{400} : \frac{x ^{2}}{400} + \frac{- x + 25}{4}

= \frac{x ^{2}}{400} + \frac{- x + 25}{4}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{- x + 25}{4} = - \frac{x}{4} + \frac{25}{4}

= \frac{x ^{2}}{400} - \frac{x}{4} + \frac{25}{4}

\frac{d ^{2}}{d x ^{2}} ((y) (cos (x) - ln (x)))

(1, 0, - 2 u) \cdot (0, 1, - 2 v)

(1 + x) (1 - x)

(x - 1) (x - 1 - 2) (x - 1 + 2)

(u - 1)^{2} (u)^{\frac{1}{2}}

What is expand (-1/20 (x-50))^2 ?
The solution to expand (-1/20 (x-50))^2 is (x^2)/(400)-x/4+25/4