What is expand (6x^2-3x+1)/((4x+1)(x^2+1)) ?

The solution to expand (6x^2-3x+1)/((4x+1)(x^2+1)) is (6x^2-3x+1)/(4x^3+4x+x^2+1)

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expand (6x^2-3x+1)/((4x+1)(x^2+1))

expand

\frac{6 x ^{2} - 3 x + 1}{( 4 x + 1 ) ( x ^{2} + 1 )}

\frac{6 x ^{2} - 3 x + 1}{4 x ^{3} + 4 x + x ^{2} + 1}

Solution steps

\frac{6 x ^{2} - 3 x + 1}{( 4 x + 1 ) ( x ^{2} + 1 )}

Expand

(4 x + 1) (x^{2} + 1) : 4 x^{3} + 4 x + x^{2} + 1

= \frac{6 x ^{2} - 3 x + 1}{4 x ^{3} + 4 x + x ^{2} + 1}

(1 + 3 i)^{13}

(sin (x) + cos (x)) x

(1 + 3 i)^{11}

\frac{1}{2} (x - \frac{1}{10} sin (10 x))

π (\frac{π}{2} - 1)

What is expand (6x^2-3x+1)/((4x+1)(x^2+1)) ?
The solution to expand (6x^2-3x+1)/((4x+1)(x^2+1)) is (6x^2-3x+1)/(4x^3+4x+x^2+1)