What is expand (2s^2-4)/((s+1)(s-2)(s-3)) ?

The solution to expand (2s^2-4)/((s+1)(s-2)(s-3)) is (2s^2-4)/(s^3-4s^2+s+6)

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expand (2s^2-4)/((s+1)(s-2)(s-3))

expand

\frac{2 s ^{2} - 4}{( s + 1 ) ( s - 2 ) ( s - 3 )}

\frac{2 s ^{2} - 4}{s ^{3} - 4 s ^{2} + s + 6}

Solution steps

\frac{2 s ^{2} - 4}{( s + 1 ) ( s - 2 ) ( s - 3 )}

Expand

(s + 1) (s - 2) (s - 3) : s^{3} - 4 s^{2} + s + 6

= \frac{2 s ^{2} - 4}{s ^{3} - 4 s ^{2} + s + 6}

cos (x) (1 + tan (x)) (1 - tan (x))

(\frac{1}{2} n - 2 v)^{10}

\frac{- x ^{2} + 2 x + 8}{( x ^{2} + 3 x + 5 ) ^{2}}

\frac{- 3 + 2 s}{s ^{2} ( s ^{2} - 9 )}

(x^{2} - \frac{2}{x})^{10}

What is expand (2s^2-4)/((s+1)(s-2)(s-3)) ?
The solution to expand (2s^2-4)/((s+1)(s-2)(s-3)) is (2s^2-4)/(s^3-4s^2+s+6)