What is expand (y^3+2y^2-1)/(sqrt(y)) ?

The solution to expand (y^3+2y^2-1)/(sqrt(y)) is (sqrt(y)(y^3+2y^2-1))/y

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expand (y^3+2y^2-1)/(sqrt(y))

expand

\frac{y ^{3} + 2 y ^{2} - 1}{y}

\frac{y ( y ^{3} + 2 y ^{2} - 1 )}{y}

Solution steps

\frac{y ^{3} + 2 y ^{2} - 1}{y}

Multiply by the conjugate

\frac{y}{y}

= \frac{( y ^{3} + 2 y ^{2} - 1 ) y}{y y}

y y = y

= \frac{y ( y ^{3} + 2 y ^{2} - 1 )}{y}

3 \cdot ((5, 10, 7) + (2, - 3, 7))

e^{2 jk w} (e^{4 jk w} + e^{- 4 jk w})

9 (sin (2 x) - cos (2 x))

\frac{( tan ( a ) + cot ( a ) ) sin ( a )}{csc ( a )}

(3 x - \frac{2}{x ^{2}})^{6}

What is expand (y^3+2y^2-1)/(sqrt(y)) ?
The solution to expand (y^3+2y^2-1)/(sqrt(y)) is (sqrt(y)(y^3+2y^2-1))/y