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Popular >

d/(d{x)}(({z})({y}{z}+{x}ln({y})-{z}^2))

Solution

\frac{d}{d x} ((z) (y z + x ln (y) - z^{2}))

Solution

ln (y) z

Solution steps

\frac{d}{d x} ((z) (y z + x ln (y) - z^{2}))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= z \frac{d}{d x} (y z + x ln (y) - z^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= z (\frac{d}{d x} (y z) + \frac{d}{d x} (x ln (y)) - \frac{d}{d x} (z^{2}))

\frac{d}{d x} (y z) = 0

\frac{d}{d x} (x ln (y)) = ln (y)

\frac{d}{d x} (z^{2}) = 0

= z (0 + ln (y) - 0)

Simplify

= ln (y) z

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Frequently Asked Questions (FAQ)

What is the d/(d{x)}(({z})({y}{z}+{x}ln({y})-{z}^2)) ?
The d/(d{x)}(({z})({y}{z}+{x}ln({y})-{z}^2)) is ln({y}){z}
What is the first d/(d{x)}(({z})({y}{z}+{x}ln({y})-{z}^2)) ?
The first d/(d{x)}(({z})({y}{z}+{x}ln({y})-{z}^2)) is ln({y}){z}