What is the first d/(dt)((x)(x^2+y^2)) ?

The first d/(dt)((x)(x^2+y^2)) is 0

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d/(dt)((x)(x^2+y^2))

\frac{d}{d t} ((x) (x^{2} + y^{2}))

0

Solution steps

\frac{d}{d t} ((x) (x^{2} + y^{2}))

Treat

x, y

as constants

Derivative of a constant:

\frac{d}{d x} (a) = 0

= 0

(x + 1) (x - 1)^{5}

\frac{x}{( 1 - 4 x ) ^{2}}

\frac{( 2 s ^{3} - s ^{2} )}{( 4 s ^{2} - 4 s + 5 ) ^{2}}

(x - 2 + 3) (x - 2 - 3)

(1 - \frac{x}{4})^{10}