What is expand e^x(3cos(3x)+9sin(3x)) ?

The solution to expand e^x(3cos(3x)+9sin(3x)) is 3e^xcos(3x)+9e^xsin(3x)

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expand e^x(3cos(3x)+9sin(3x))

expand

e^{x} (3 cos (3 x) + 9 sin (3 x))

3 e^{x} cos (3 x) + 9 e^{x} sin (3 x)

Solution steps

e^{x} (3 cos (3 x) + 9 sin (3 x))

Apply the distributive law:

a (b + c) = ab + a c

a = e^{x}, b = 3 cos (3 x), c = 9 sin (3 x)

= e^{x} \cdot 3 cos (3 x) + e^{x} \cdot 9 sin (3 x)

= 3 e^{x} cos (3 x) + 9 e^{x} sin (3 x)

s^{2} (2 + \frac{2}{s})

1 + \frac{K ( s + 1 ) ( s + 2.69 )}{s ^{3}}

\frac{1260}{( 2 x + 3 ) ^{3}}

\frac{5 n ( n + 1 )}{2}

(16 - r^{2}) r^{2} cos (x)

What is expand e^x(3cos(3x)+9sin(3x)) ?
The solution to expand e^x(3cos(3x)+9sin(3x)) is 3e^xcos(3x)+9e^xsin(3x)