What is expand (2x+3y=20,)(x-2y=3) ?

The solution to expand (2x+3y=20,)(x-2y=3) is 2x^2-4xy=3

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expand (2x+3y=20,)(x-2y=3)

expand

(2 x + 3 y = 20,) (x - 2 y = 3)

2 x^{2} - 4 x y = 3

Solution steps

(2 x + 3 y = 20,) (x - 2 y = 3)

= (2 x + 3 \cdot 20 =, y) (x - 2 \cdot 3 = y)

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 2 x, b = 3 y = 20,, c = x, d = - 2 y = 3

2 xx + 2 x (- 2 y = 3) + 3 y = 20, x + 3 y = 20, (- 2 y = 3)

Apply minus-plus rules

+ (- a) = - a

2 xx - 2 \cdot 2 x y = 3 + 3 y = 20, x - 3 y = 20, 2 y = 3

Expand

2 xx - 2 \cdot 2 x y : 2 x^{2} - 4 x y

2 x^{2} - 4 x y = 3

x^{2} (x - 9)^{5} d x

[(t + 1)^{2} + e^{t - 2}] U (t - 2)

(D + x) (D + 1) e^{x}

(1 + i)^{5}

(3 + i)^{26}

What is expand (2x+3y=20,)(x-2y=3) ?
The solution to expand (2x+3y=20,)(x-2y=3) is 2x^2-4xy=3