What is expand (e^u+e^{-u})(e^u-e^{-u}) ?

The solution to expand (e^u+e^{-u})(e^u-e^{-u}) is e^{2u}-e^{-2u}

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expand (e^u+e^{-u})(e^u-e^{-u})

expand

(e^{u} + e^{- u}) (e^{u} - e^{- u})

e^{2 u} - e^{- 2 u}

Solution steps

(e^{u} + e^{- u}) (e^{u} - e^{- u})

Apply Difference of Two Squares Formula:

(a + b) (a - b) = a^{2} - b^{2}

a = e^{u}, b = e^{- u}

= (e^{u})^{2} - (e^{- u})^{2}

Simplify

(e^{u})^{2} - (e^{- u})^{2} : e^{2 u} - e^{- 2 u}

= e^{2 u} - e^{- 2 u}

(2 cos (x) - 2)^{2}

, x (x 2 + y^{2})

(3 + 1)^{7}

\frac{4 x + 5}{( x + 5 ) ( 5 x - 1 )}

\frac{d}{d t} ((k) (s k^{a} - nk))

What is expand (e^u+e^{-u})(e^u-e^{-u}) ?
The solution to expand (e^u+e^{-u})(e^u-e^{-u}) is e^{2u}-e^{-2u}