What is expand (1-tan(θ))tan(2θ) ?

The solution to expand (1-tan(θ))tan(2θ) is tan(2θ)-tan(2θ)tan(θ)

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expand (1-tan(θ))tan(2θ)

expand

(1 - tan (θ)) tan (2 θ)

tan (2 θ) - tan (2 θ) tan (θ)

Solution steps

(1 - tan (θ)) tan (2 θ)

= tan (2 θ) (1 - tan (θ))

Apply the distributive law:

a (b - c) = ab - a c

tan (2 θ) (1 - tan (θ)) = tan (2 θ) \cdot 1 - tan (2 θ) tan (θ)

= tan (2 θ) \cdot 1 - tan (2 θ) tan (θ)

Apply rule:

a \cdot 1 = a

tan (2 θ) \cdot 1 = tan (2 θ)

= tan (2 θ) - tan (2 θ) tan (θ)

- \frac{2 x ( - x ^{2} + 189 )}{( x ^{2} + 63 ) ^{3}}

(1 + x^{2}) (1 + x^{2})

(e^{\frac{x}{2}} + e^{- \frac{x}{2}})^{2}

2 (7 + 4)

What is expand (1-tan(θ))tan(2θ) ?
The solution to expand (1-tan(θ))tan(2θ) is tan(2θ)-tan(2θ)tan(θ)