What are the solutions to the equation x^2+10x=-21 ?

The solutions to the equation x^2+10x=-21 are x=-3,x=-7

Find the zeros of x^2+10x=-21

The zeros of x^2+10x=-21 are x=-3,x=-7

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x^{2} + 10 x = - 21

x = - 3, x = - 7

Solution steps

x^{2} + 10 x = - 21

Move

21

to the left side

x^{2} + 10 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 21 = 4

x_{1, 2} = \frac{- 10 \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 4}{2 \cdot 1}, x_{2} = \frac{- 10 - 4}{2 \cdot 1}

x = \frac{- 10 + 4}{2 \cdot 1} : - 3

x = \frac{- 10 - 4}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

x = - 3, x = - 7

\frac{4}{1 + i} - \frac{2}{1 - i}

x^{2} - 5 x + 4 \leq 0

3 x^{2} + 3 x - 60

4 \cdot (\frac{1}{2})^{- 1}

- 2 ∣ - x - 5 ∣ = - 10

What are the solutions to the equation x^2+10x=-21 ?
The solutions to the equation x^2+10x=-21 are x=-3,x=-7
Find the zeros of x^2+10x=-21
The zeros of x^2+10x=-21 are x=-3,x=-7