What is ((4x^2y)/3+y)((2x^4y^2)/5+2) ?

The solution to ((4x^2y)/3+y)((2x^4y^2)/5+2) is ((3y+4x^2y)(10+2x^4y^2))/(15)

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simplify ((4x^2y)/3+y)((2x^4y^2)/5+2)

simplify

(\frac{4 x ^{2} y}{3} + y) (\frac{2 x ^{4} y ^{2}}{5} + 2)

\frac{( 3 y + 4 x ^{2} y ) ( 10 + 2 x ^{4} y ^{2} )}{15}

Solution steps

(\frac{4 x ^{2} y}{3} + y) (\frac{2 x ^{4} y ^{2}}{5} + 2)

Simplify

\frac{4 x ^{2} y}{3} + y : \frac{3 y + 4 x ^{2} y}{3}

= \frac{3 y + 4 x ^{2} y}{3} (\frac{2 x ^{4} y ^{2}}{5} + 2)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 3 y + 4 x ^{2} y ) ( \frac{2 x ^{4} y ^{2}}{5} + 2 )}{3}

Simplify

(3 y + 4 x^{2} y) (\frac{2 x ^{4} y ^{2}}{5} + 2) : \frac{( 3 y + 4 x ^{2} y ) ( 10 + 2 x ^{4} y ^{2} )}{5}

= \frac{\frac{( 3 y + 4 x ^{2} y ) ( 10 + 2 x ^{4} y ^{2} )}{5}}{3}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{( 3 y + 4 x ^{2} y ) ( 10 + 2 x ^{4} y ^{2} )}{5 \cdot 3}

Multiply the numbers:

5 \cdot 3 = 15

= \frac{( 3 y + 4 x ^{2} y ) ( 10 + 2 x ^{4} y ^{2} )}{15}

(2 - 47) \cdot (23 - 5)

e^{x} (x - 4)

(3 x + 2) 2 x + 1

(u + 1) (u)^{\frac{1}{2}}

What is ((4x^2y)/3+y)((2x^4y^2)/5+2) ?
The solution to ((4x^2y)/3+y)((2x^4y^2)/5+2) is ((3y+4x^2y)(10+2x^4y^2))/(15)