What is expand ((x-3)(x-1))/((x+4)(x-2)) ?

The solution to expand ((x-3)(x-1))/((x+4)(x-2)) is (x^2-4x+3)/(x^2+2x-8)

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expand ((x-3)(x-1))/((x+4)(x-2))

expand

\frac{( x - 3 ) ( x - 1 )}{( x + 4 ) ( x - 2 )}

\frac{x ^{2} - 4 x + 3}{x ^{2} + 2 x - 8}

Solution steps

\frac{( x - 3 ) ( x - 1 )}{( x + 4 ) ( x - 2 )}

Expand

(x + 4) (x - 2) : x^{2} + 2 x - 8

= \frac{( x - 3 ) ( x - 1 )}{x ^{2} + 2 x - 8}

Expand

(x - 3) (x - 1) : x^{2} - 4 x + 3

= \frac{x ^{2} - 4 x + 3}{x ^{2} + 2 x - 8}

\frac{1}{x ( k - x )}

\frac{12 ( x + 1 ) ( x - 1 )}{( x ^{2} + 3 ) ^{3}}

\frac{2 s + 2}{( s ^{2} + 1 ) ( s - 1 ) ^{3}}

[(cos (t))^{2} (1 + e^{2 t})^{3}]

2 (5 - 11)

What is expand ((x-3)(x-1))/((x+4)(x-2)) ?
The solution to expand ((x-3)(x-1))/((x+4)(x-2)) is (x^2-4x+3)/(x^2+2x-8)