What is expand (x+1+i)(x+1-i) ?

The solution to expand (x+1+i)(x+1-i) is x^2+2x+2

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expand (x+1+i)(x+1-i)

expand

(x + 1 + i) (x + 1 - i)

x^{2} + 2 x + 2

Solution steps

(x + 1 + i) (x + 1 - i)

Distribute parentheses

= xx + x \cdot 1 + x (- i) + 1 \cdot x + 1 \cdot 1 + 1 \cdot (- i) + i x + i 1 + i (- i)

Simplify

xx + x \cdot 1 + x (- i) + 1 \cdot x + 1 \cdot 1 + 1 \cdot (- i) + i x + i 1 + i (- i) : x^{2} + 2 x + 2

= x^{2} + 2 x + 2

\frac{2 ( x - 7 )}{7 ( x + 3 )}

(2 i + 3)^{4} + (2 i - 3)^{4}

\frac{( \frac{x}{y} ) ^{\frac{1}{4}}}{( \frac{y}{x} ) ^{\frac{3}{4}}}

(x - 3) (x - 3 + 5) (x - 3 - 5)

(1 + 3 z + z^{3})^{6}

What is expand (x+1+i)(x+1-i) ?
The solution to expand (x+1+i)(x+1-i) is x^2+2x+2