What is expand log_{6}(x)(x-1)^2 ?

The solution to expand log_{6}(x)(x-1)^2 is x^2log_{6}(x)-2xlog_{6}(x)+log_{6}(x)

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expand log_{6}(x)(x-1)^2

expand

lo g_{6} (x) (x - 1)^{2}

x^{2} lo g_{6} (x) - 2 x lo g_{6} (x) + lo g_{6} (x)

Solution steps

lo g_{6} (x) (x - 1)^{2}

Expand

(x - 1)^{2} : x^{2} - 2 x + 1

= lo g_{6} (x) (x^{2} - 2 x + 1)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

lo g_{6} (x) (x^{2} - 2 x + 1) = lo g_{6} (x) x^{2} + lo g_{6} (x) (- 2 x) + lo g_{6} (x) \cdot 1

= lo g_{6} (x) x^{2} + lo g_{6} (x) (- 2 x) + lo g_{6} (x) \cdot 1

Simplify

lo g_{6} (x) x^{2} + lo g_{6} (x) (- 2 x) + lo g_{6} (x) \cdot 1 : x^{2} lo g_{6} (x) - 2 x lo g_{6} (x) + lo g_{6} (x)

= x^{2} lo g_{6} (x) - 2 x lo g_{6} (x) + lo g_{6} (x)

1 - (sin (A) + cos (A)) 2

(2 - 3 x) (x - 1)^{2} (x - 1 + 3) (x - 1 - 3)

x (x^{2} + 1)

(2 x + 1)^{2} (4 x)

\frac{m + 5}{7 ( m - 5 )}

What is expand log_{6}(x)(x-1)^2 ?
The solution to expand log_{6}(x)(x-1)^2 is x^2log_{6}(x)-2xlog_{6}(x)+log_{6}(x)