What are the solutions to the equation x^2+x/5 =404 ?

The solutions to the equation x^2+x/5 =404 are x=20,x=-101/5

Find the zeros of x^2+x/5 =404

The zeros of x^2+x/5 =404 are x=20,x=-101/5

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x^{2} + \frac{x}{5} = 404

x = 20, x = - \frac{101}{5}

Solution steps

x^{2} + \frac{x}{5} = 404

Multiply both sides by

5

5 x^{2} + x = 2020

Move

2020

to the left side

5 x^{2} + x - 2020 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 2020 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 2020) = 201

x_{1, 2} = \frac{- 1 \pm 201}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 1 + 201}{2 \cdot 5}, x_{2} = \frac{- 1 - 201}{2 \cdot 5}

x = \frac{- 1 + 201}{2 \cdot 5} : 20

x = \frac{- 1 - 201}{2 \cdot 5} : - \frac{101}{5}

The solutions to the quadratic equation are:

x = 20, x = - \frac{101}{5}

62 5^{\frac{5}{4}}

- x^{2} - 3 x + 18 \leq 0

(6 + 7 i) (3 - 7 i)

∣ 3 x - 6 ∣ > 15

10 X - 18 > 12

What are the solutions to the equation x^2+x/5 =404 ?
The solutions to the equation x^2+x/5 =404 are x=20,x=-101/5
Find the zeros of x^2+x/5 =404
The zeros of x^2+x/5 =404 are x=20,x=-101/5