What is expand sin((ax-bt)^2)(ax-bt) ?

The solution to expand sin((ax-bt)^2)(ax-bt) is axsin((ax-bt)^2)-btsin((ax-bt)^2)

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expand sin((ax-bt)^2)(ax-bt)

expand

sin ((a x - b t)^{2}) (a x - b t)

a x sin ((a x - b t)^{2}) - b t sin ((a x - b t)^{2})

Solution steps

sin ((a x - b t)^{2}) (a x - b t)

Apply the distributive law:

a (b - c) = ab - a c

sin ((a x - b t)^{2}) (a x - b t) = sin ((a x - b t)^{2}) a x - sin ((a x - b t)^{2}) b t

= sin ((a x - b t)^{2}) a x - sin ((a x - b t)^{2}) b t

= a x sin ((a x - b t)^{2}) - b t sin ((a x - b t)^{2})

\frac{a ^{2}}{b ^{4} c}

- \frac{6 x}{( 3 x ^{2} + 4 ) ^{2}}

cos^{2} (x) (sec (x) - 1)

ln (\frac{( 2 x + 7 )}{y ^{3} + 3})

\frac{4 q ^{2} - 4 q r + b r - q}{4 ( b r - q ) ( q - 1 ) ^{2}}

What is expand sin((ax-bt)^2)(ax-bt) ?
The solution to expand sin((ax-bt)^2)(ax-bt) is axsin((ax-bt)^2)-btsin((ax-bt)^2)