What are the solutions to the equation m^2+2m+2=0 ?

The solutions to the equation m^2+2m+2=0 are m=-1+i,m=-1-i

Find the zeros of m^2+2m+2=0

The zeros of m^2+2m+2=0 are m=-1+i,m=-1-i

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m^{2} + 2 m + 2 = 0

m = - 1 + i, m = - 1 - i

Solution steps

m^{2} + 2 m + 2 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 2 : 2 i

m_{1, 2} = \frac{- 2 \pm 2 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 2 + 2 i}{2 \cdot 1}, m_{2} = \frac{- 2 - 2 i}{2 \cdot 1}

m = \frac{- 2 + 2 i}{2 \cdot 1} : - 1 + i

m = \frac{- 2 - 2 i}{2 \cdot 1} : - 1 - i

The solutions to the quadratic equation are:

m = - 1 + i, m = - 1 - i

x^{5} y^{- 2}

\frac{e ^{2 x + 3}}{2 - x} < 0

(a^{- \frac{1}{2}})^{3}

\frac{2 b}{3} + 8 = 20

7 = \frac{3}{9} x

What are the solutions to the equation m^2+2m+2=0 ?
The solutions to the equation m^2+2m+2=0 are m=-1+i,m=-1-i
Find the zeros of m^2+2m+2=0
The zeros of m^2+2m+2=0 are m=-1+i,m=-1-i