What is expand 1/4 (1-sin(4x))-2cos^2(x)sin^2(x) ?

The solution to expand 1/4 (1-sin(4x))-2cos^2(x)sin^2(x) is (1-sin(4x))/4-2cos^2(x)sin^2(x)

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expand 1/4 (1-sin(4x))-2cos^2(x)sin^2(x)

expand

\frac{1}{4} (1 - sin (4 x)) - 2 cos^{2} (x) sin^{2} (x)

\frac{1 - sin ( 4 x )}{4} - 2 cos^{2} (x) sin^{2} (x)

Solution steps

\frac{1}{4} (1 - sin (4 x)) - 2 cos^{2} (x) sin^{2} (x)

Apply the distributive law:

a (b - c) = ab - a c

\frac{1}{4} (1 - sin (4 x)) = \frac{1}{4} \cdot 1 - \frac{1}{4} sin (4 x)

= \frac{1}{4} \cdot 1 - \frac{1}{4} sin (4 x) - 2 cos^{2} (x) sin^{2} (x)

Simplify

\frac{1}{4} \cdot 1 - \frac{1}{4} sin (4 x) : \frac{1 - sin ( 4 x )}{4}

= \frac{1 - sin ( 4 x )}{4} - 2 cos^{2} (x) sin^{2} (x)

(3 x - 3) (3 x + 1)

10 (sec^{2} (x) + csc^{2} (x))

cos (x) (- sin (x) + 1)

π (x + π)

\frac{1}{( s - x ) ( s - y )}

What is expand 1/4 (1-sin(4x))-2cos^2(x)sin^2(x) ?
The solution to expand 1/4 (1-sin(4x))-2cos^2(x)sin^2(x) is (1-sin(4x))/4-2cos^2(x)sin^2(x)