What are the solutions to the equation 4x^2=-13x-3 ?

The solutions to the equation 4x^2=-13x-3 are x=-1/4 ,x=-3

Find the zeros of 4x^2=-13x-3

The zeros of 4x^2=-13x-3 are x=-1/4 ,x=-3

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4 x^{2} = - 13 x - 3

x = - \frac{1}{4}, x = - 3

Decimal Notation

x = - 0.25, x = - 3

Solution steps

4 x^{2} = - 13 x - 3

Move

3

to the left side

4 x^{2} + 3 = - 13 x

Move

13 x

to the left side

4 x^{2} + 3 + 13 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 13 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

1 3^{2} - 4 \cdot 4 \cdot 3 = 11

x_{1, 2} = \frac{- 13 \pm 11}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 13 + 11}{2 \cdot 4}, x_{2} = \frac{- 13 - 11}{2 \cdot 4}

x = \frac{- 13 + 11}{2 \cdot 4} : - \frac{1}{4}

x = \frac{- 13 - 11}{2 \cdot 4} : - 3

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = - 3

\frac{1}{- 4 i}

8^{\frac{7}{3}}

x - 2 = 4 - x

x^{2} - \frac{5}{2} x + 1 = 0

0.2 \cdot y \cdot (1 - (\frac{y}{5})) - 0.24 = 0

What are the solutions to the equation 4x^2=-13x-3 ?
The solutions to the equation 4x^2=-13x-3 are x=-1/4 ,x=-3
Find the zeros of 4x^2=-13x-3
The zeros of 4x^2=-13x-3 are x=-1/4 ,x=-3