What is expand (2x+1)(x^2-x^4=5) ?

The solution to expand (2x+1)(x^2-x^4=5) is -2x^5+2x^3=5

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expand (2x+1)(x^2-x^4=5)

expand

(2 x + 1) (x^{2} - x^{4} = 5)

- 2 x^{5} + 2 x^{3} = 5

Solution steps

(2 x + 1) (x^{2} - x^{4} = 5)

= (2 x + 1) (x^{2} - 5 = x^{4})

Apply FOIL method:

(a + b) (c + d) = a c + a d + b c + b d

a = 2 x, b = 1, c = x^{2}, d = - x^{4} = 5

= 2 x x^{2} + 2 x (- x^{4} = 5) + 1 \cdot x^{2} + 1 \cdot (- x^{4} = 5)

Apply minus-plus rules

+ (- a) = - a

2 x^{2} x - 2 x^{4} x = 5 + 1 \cdot x^{2} - 1 \cdot x^{4} = 5

Expand

2 x^{2} x - 2 x^{4} x : - 2 x^{5} + 2 x^{3}

- 2 x^{5} + 2 x^{3} = 5

- \frac{4}{s ^{2} ( s - 2 )}

15 (π^{2} - 4) - \frac{π ^{2}}{2}

x^{4} (\frac{x ^{2}}{2} - 2)

\frac{2 x - 4}{( x + 1 ) ^{4}}

\frac{1}{4} w L (x - \frac{L}{4})^{2}

What is expand (2x+1)(x^2-x^4=5) ?
The solution to expand (2x+1)(x^2-x^4=5) is -2x^5+2x^3=5