What is (4x^2+x-3/2)(6x-8) ?

The solution to (4x^2+x-3/2)(6x-8) is (8x^2+2x-3)(3x-4)

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simplify (4x^2+x-3/2)(6x-8)

simplify

(4 x^{2} + x - \frac{3}{2}) (6 x - 8)

(8 x^{2} + 2 x - 3) (3 x - 4)

Solution steps

(4 x^{2} + x - \frac{3}{2}) (6 x - 8)

Simplify

4 x^{2} + x - \frac{3}{2} : \frac{8 x ^{2} + 2 x - 3}{2}

= \frac{8 x ^{2} + 2 x - 3}{2} (6 x - 8)

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( 8 x ^{2} + 2 x - 3 ) ( 6 x - 8 )}{2}

Factor

6 x - 8 : 2 (3 x - 4)

= \frac{( 8 x ^{2} + 2 x - 3 ) \cdot 2 ( 3 x - 4 )}{2}

Cancel the common factor:

2

= (8 x^{2} + 2 x - 3) (3 x - 4)

(x - (- 2 - 3 i)) (x - (- 2 + 3 i))

\frac{x}{( x - 1 ) ( x - 2 ) ^{2}}

A (1, - 2) y B (- 3, - 2)

(\frac{2}{x} - y^{2})^{12}

\frac{\frac{4}{\frac{4}{7} \cdot 0.3}}{\frac{2.88}{4.8}}

What is (4x^2+x-3/2)(6x-8) ?
The solution to (4x^2+x-3/2)(6x-8) is (8x^2+2x-3)(3x-4)