What is 10(log_{10}(141)+12) ?

The solution to 10(log_{10}(141)+12) is 10log_{10}(141)+120

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simplify 10(log_{10}(141)+12)

simplify

10 (lo g_{10} (141) + 12)

10 lo g_{10} (141) + 120

Decimal Notation

141.49219 \dots

Solution steps

10 (lo g_{10} (141) + 12)

Apply the distributive law:

a (b + c) = ab + a c

10 (lo g_{10} (141) + 12) = 10 lo g_{10} (141) + 10 \cdot 12

= 10 lo g_{10} (141) + 10 \cdot 12

Multiply the numbers:

10 \cdot 12 = 120

= 10 lo g_{10} (141) + 120

cot (x) (\frac{1}{3 cos ( x )} + tan (x))

(sin (x) + x cos (x)) (3 cos (x sin (x)))

\frac{4 x ^{2}}{( x - 5 ) ^{2} ( x + 5 ) ^{2}}

(\frac{x y ^{2}}{2} = \frac{y}{x} + c) \cdot 2

22 (7 + 33)

What is 10(log_{10}(141)+12) ?
The solution to 10(log_{10}(141)+12) is 10log_{10}(141)+120