What is expand 1/((x-2)(x^2+4)) ?

The solution to expand 1/((x-2)(x^2+4)) is 1/(x^3+4x-2x^2-8)

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expand 1/((x-2)(x^2+4))

expand

\frac{1}{( x - 2 ) ( x ^{2} + 4 )}

\frac{1}{x ^{3} + 4 x - 2 x ^{2} - 8}

Solution steps

\frac{1}{( x - 2 ) ( x ^{2} + 4 )}

Expand

(x - 2) (x^{2} + 4) : x^{3} + 4 x - 2 x^{2} - 8

= \frac{1}{x ^{3} + 4 x - 2 x ^{2} - 8}

(cos (x)) (cos (x) - sin (x))

A (1, - 4) y B (6, 13)

\frac{2 ( e ^{- \frac{3 t}{2}} - 1 )}{3 e ^{- \frac{t}{2}}}

(λ - \frac{1}{2})^{2} (λ - \frac{29}{2})

\frac{15 x ^{2} - x + 2}{( x - 5 ) ( 3 x ^{2} + 4 x - 2 )}

What is expand 1/((x-2)(x^2+4)) ?
The solution to expand 1/((x-2)(x^2+4)) is 1/(x^3+4x-2x^2-8)