What is 2(2^{n/2}-1) ?

The solution to 2(2^{n/2}-1) is 2*2^{n/2}-2

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simplify 2(2^{n/2}-1)

simplify

2 (2^{\frac{n}{2}} - 1)

2 \cdot 2^{\frac{n}{2}} - 2

Solution steps

2 (2^{\frac{n}{2}} - 1)

Apply the distributive law:

a (b - c) = ab - a c

2 (2^{\frac{n}{2}} - 1) = 2 \cdot 2^{\frac{n}{2}} - 2 \cdot 1

= 2 \cdot 2^{\frac{n}{2}} - 2 \cdot 1

Multiply the numbers:

2 \cdot 1 = 2

= 2 \cdot 2^{\frac{n}{2}} - 2

(1 - 2 z i)^{2}

e^{2 t} \cdot t^{2} \cdot U (t - 3)

t (t^{2} + 3 t + 2)

(sec (x) - tan (x)) cot (x) - csc (x)

\frac{24}{( 1 0 ^{2} )}