What are the solutions to the equation q^2+34=35 ?

The solutions to the equation q^2+34=35 are q=1,q=-1

Find the zeros of q^2+34=35

The zeros of q^2+34=35 are q=1,q=-1

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q^{2} + 34 = 35

q = 1, q = - 1

Solution steps

q^{2} + 34 = 35

Move

34

to the right side

q^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

q = 1, q = - 1

1 = 1

- 1 = - 1

q = 1, q = - 1

\frac{2}{10} - \frac{3}{10}

\frac{9 x ^{2} - 6 x + 1}{x ^{3} - x ^{2}} \leq 0

4 x^{2} + 10 x = - 3

2.61704 \cdot (\frac{1}{2})^{\frac{1000}{24100}}

- 0.5244 = \frac{x - 54}{16}

What are the solutions to the equation q^2+34=35 ?
The solutions to the equation q^2+34=35 are q=1,q=-1
Find the zeros of q^2+34=35
The zeros of q^2+34=35 are q=1,q=-1