What is expand x^{12}(2x^2+6x-8)^2 ?

The solution to expand x^{12}(2x^2+6x-8)^2 is 4x^{16}+24x^{15}+4x^{14}-96x^{13}+64x^{12}

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expand x^{12}(2x^2+6x-8)^2

expand

x^{12} (2 x^{2} + 6 x - 8)^{2}

4 x^{16} + 24 x^{15} + 4 x^{14} - 96 x^{13} + 64 x^{12}

Solution steps

x^{12} (2 x^{2} + 6 x - 8)^{2}

(2 x^{2} + 6 x - 8)^{2} = 4 x^{4} + 24 x^{3} + 4 x^{2} - 96 x + 64

= x^{12} (4 x^{4} + 24 x^{3} + 4 x^{2} - 96 x + 64)

Distribute parentheses

= x^{12} \cdot 4 x^{4} + x^{12} \cdot 24 x^{3} + x^{12} \cdot 4 x^{2} + x^{12} (- 96 x) + x^{12} \cdot 64

Apply minus-plus rules

+ (- a) = - a

= 4 x^{12} x^{4} + 24 x^{12} x^{3} + 4 x^{12} x^{2} - 96 x^{12} x + 64 x^{12}

Simplify

4 x^{12} x^{4} + 24 x^{12} x^{3} + 4 x^{12} x^{2} - 96 x^{12} x + 64 x^{12} : 4 x^{16} + 24 x^{15} + 4 x^{14} - 96 x^{13} + 64 x^{12}

= 4 x^{16} + 24 x^{15} + 4 x^{14} - 96 x^{13} + 64 x^{12}

(3 + e^{- x})^{2}

(\frac{6}{100}) + 1.61 (\frac{9.5}{100} - \frac{6}{100}) + 1.5

\frac{19 x - 34}{( x - 2 ) ( x ^{2} + 1 )}

(cos (x) + k) (k - sin (x))

x (x - 3)^{2}

What is expand x^{12}(2x^2+6x-8)^2 ?
The solution to expand x^{12}(2x^2+6x-8)^2 is 4x^{16}+24x^{15}+4x^{14}-96x^{13}+64x^{12}