What is (x^{3/2}-4x)(x^4-3/(x^2)+2) ?

The solution to (x^{3/2}-4x)(x^4-3/(x^2)+2) is ((x^{3/2}-4x)(x^6-3+2x^2))/(x^2)

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simplify (x^{3/2}-4x)(x^4-3/(x^2)+2)

simplify

(x^{\frac{3}{2}} - 4 x) (x^{4} - \frac{3}{x ^{2}} + 2)

\frac{( x ^{\frac{3}{2}} - 4 x ) ( x ^{6} - 3 + 2 x ^{2} )}{x ^{2}}

Solution steps

(x^{\frac{3}{2}} - 4 x) (x^{4} - \frac{3}{x ^{2}} + 2)

Join

x^{4} - \frac{3}{x ^{2}} + 2 : \frac{x ^{6} - 3 + 2 x ^{2}}{x ^{2}}

= (x^{\frac{3}{2}} - 4 x) \frac{x ^{6} - 3 + 2 x ^{2}}{x ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x ^{\frac{3}{2}} - 4 x ) ( x ^{6} - 3 + 2 x ^{2} )}{x ^{2}}

\frac{1}{( x + 2 ) ( x - 1 )}

(4 x + \frac{1}{k x})^{7}

\frac{5}{2} (ln (5) - 1)

What is (x^{3/2}-4x)(x^4-3/(x^2)+2) ?
The solution to (x^{3/2}-4x)(x^4-3/(x^2)+2) is ((x^{3/2}-4x)(x^6-3+2x^2))/(x^2)