What is expand 5cos(t)(4sin(t)-9tan(t)) ?

The solution to expand 5cos(t)(4sin(t)-9tan(t)) is 20cos(t)sin(t)-45sin(t)

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expand 5cos(t)(4sin(t)-9tan(t))

expand

5 cos (t) (4 sin (t) - 9 tan (t))

20 cos (t) sin (t) - 45 sin (t)

Solution steps

5 cos (t) (4 sin (t) - 9 tan (t))

Apply the distributive law:

a (b - c) = ab - a c

5 cos (t) (4 sin (t) - 9 tan (t)) = 5 cos (t) \cdot 4 sin (t) - 5 cos (t) \cdot 9 tan (t)

= 5 cos (t) \cdot 4 sin (t) - 5 cos (t) \cdot 9 tan (t)

Simplify

5 cos (t) \cdot 4 sin (t) - 5 cos (t) \cdot 9 tan (t) : 20 cos (t) sin (t) - 45 sin (t)

= 20 cos (t) sin (t) - 45 sin (t)

(x^{2} + 1) (arccot (x))

- sin (t) (t + sin (t))^{2}

arctan (f (5 x^{5} + 4))

cos ((5 + n) π)

(43 - 7) (43 - 37)^{'}

What is expand 5cos(t)(4sin(t)-9tan(t)) ?
The solution to expand 5cos(t)(4sin(t)-9tan(t)) is 20cos(t)sin(t)-45sin(t)