What is expand ((3x-L)(L+3x))/(18) ?

The solution to expand ((3x-L)(L+3x))/(18) is (x^2)/2-(L^2)/(18)

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expand ((3x-L)(L+3x))/(18)

expand

\frac{( 3 x - L ) ( L + 3 x )}{18}

\frac{x ^{2}}{2} - \frac{L ^{2}}{18}

Solution steps

\frac{( 3 x - L ) ( L + 3 x )}{18}

Expand

(3 x - L) (L + 3 x) : 9 x^{2} - L^{2}

= \frac{9 x ^{2} - L ^{2}}{18}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{9 x ^{2} - L ^{2}}{18} = \frac{9 x ^{2}}{18} - \frac{L ^{2}}{18}

= \frac{9 x ^{2}}{18} - \frac{L ^{2}}{18}

Cancel

\frac{9 x ^{2}}{18} : \frac{x ^{2}}{2}

= \frac{x ^{2}}{2} - \frac{L ^{2}}{18}

(x^{3} - 1) 3 x^{2} - 2 x

\frac{( 1 + x ) ^{2}}{2}

\frac{d ^{2}}{d k ^{2}} ((x) (e^{2 x} - k x))

\frac{1}{2 ( 12 a - 8 b )}

(- 1 - x) \cdot (- 4 - y) - (- x) \cdot (- y)

What is expand ((3x-L)(L+3x))/(18) ?
The solution to expand ((3x-L)(L+3x))/(18) is (x^2)/2-(L^2)/(18)