What is expand ((x+1)(x-3)3)/((x+4)(x-1)) ?

The solution to expand ((x+1)(x-3)3)/((x+4)(x-1)) is (3x^2-6x-9)/(x^2+3x-4)

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expand ((x+1)(x-3)3)/((x+4)(x-1))

expand

\frac{( x + 1 ) ( x - 3 ) 3}{( x + 4 ) ( x - 1 )}

\frac{3 x ^{2} - 6 x - 9}{x ^{2} + 3 x - 4}

Solution steps

\frac{( x + 1 ) ( x - 3 ) \cdot 3}{( x + 4 ) ( x - 1 )}

Expand

(x + 4) (x - 1) : x^{2} + 3 x - 4

= \frac{3 ( x + 1 ) ( x - 3 )}{x ^{2} + 3 x - 4}

Expand

(x + 1) (x - 3) \cdot 3 : 3 x^{2} - 6 x - 9

= \frac{3 x ^{2} - 6 x - 9}{x ^{2} + 3 x - 4}

\frac{( x ^{2} + 2 ) d x}{x ^{3} - 7 x ^{2} + 10 x}

\frac{x ( 10 - x ^{2} )}{2}

\frac{x A + B + 4 A}{( x - 1 ) ( x - 3 )}

\frac{1}{2 ( x + 2 )}

- 3 (- 2 cos (x) + 3 cos^{3} (x))

What is expand ((x+1)(x-3)3)/((x+4)(x-1)) ?
The solution to expand ((x+1)(x-3)3)/((x+4)(x-1)) is (3x^2-6x-9)/(x^2+3x-4)